All categories

2 years ago

What is the area of this trapezoid? asap

Mathematics

2 answers:

Drupady [299]2 years ago

8 0

Answer:

209 ft^2

Step-by-step explanation:

There are two methods

the first one is

(b1 + b2)/2 * h = area

(15+23)/2 * 11 = 209

The second one is

((b2 - b1) * h)/2 + (b1 * h) = area

(8 * 11)/2 + (15 * 11) = 209

**double check with calculator

dezoksy [38]2 years ago

4 0

Answer:

3796 Answer D

Step-by-step explanation:

I multiplied all of the slides. I hope this helps.

You might be interested in

42 is 8% of what number

Setler [38]

8%=0.08
42÷0.08=525
So your answer is 525

7 0

2 years ago

Read 2 more answers

X2 + 3x - 108 = 0 What is the answer?

worty [1.4K]

Answer:

The answer is x=9 and/or x = -12

Step-by-step explanation:

This is a quadratic formula meaning that you must take the a value (1) b value (3) and the c value (108) and plug it into the quadratic formula.

$\frac{-3±\sqrt{9+4*1*-108} }{2}$

which simplifies to -3 add or subtract the sqrt of 441 divided by two.

5 0

3 years ago

4. Five cards are randomly chosen from a deck of 52 (13 denominations with 4 suits). a. How many ways are there to receive 5 car

yan [13]

Answer:

There are 2,598,960 ways to receive 5 cards from a deck of 52.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

a. How many ways are there to receive 5 cards from a deck of 52?

$C_{52,5} = \frac{52!}{5!(47)!} = 2598960$

There are 2,598,960 ways to receive 5 cards from a deck of 52.

4 0

2 years ago

4 1/3 - 2 1/2 please help Explanation:

galben [10]

Answer:

1 $\frac{5}{6}$

Step-by-step explanation:

First convert this mix number into a improper number

13/3-5/2

Then find the LCM of the denominator

26/6-15/6

Now simplify

11/6

1 $\frac{5}{6}$

Hope you got it

If you have any question just ask me

If you think this is the best answer please mark me as brainliest

8 0

2 years ago

Read 2 more answers

Harold, a marina manager, purchased two boats. He then sold the boats, the first

zaharov [31]

Harold paid $ 16,632 and $ 38,808 for each of the boats.

Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:

55 x 0.6 + 45 x 0.4 = 51
65 x 0.6 + 35 x 0.4 = 53
70 x 0.6 + 35 x 0.4 = 54

88,704 x 0.7 = 62,092.80
160 = 62,092.80
100 = X
100 x 62,092.80 / 160 = X
38.808 = X

88,704 x 0.3 = 26,611.20
140 = 26,611.20
100 = X
100 x 26,611.20 / 160 = X
16,632 = X

Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.

Learn more in brainly.com/question/21446500

7 0

2 years ago