<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
Answer:
cos4B =1-8sin^2(B)+8sin^4(B)
Step-by-step explanation:
cos4B =1-8sin^2(B)+8sin^4(B)
I hope this helps you
3t÷3 < -15÷3
t < -5
18=3+36x-50x-55
18=3-14x-55
18=-14x-52
70=-14x
x=-5
Answer:
(2x+3)3 :)
Step-by-step explanation: