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Evgesh-ka [11]
3 years ago
5

Use the data in this stem-and-leaf plot to answer the question.

Mathematics
1 answer:
hram777 [196]3 years ago
6 0
There were 11 dogs in the sample
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1. Which relation represents a function?
weqwewe [10]
Why is the ecuation this math i do not undertand
8 0
3 years ago
Please helpp with my math hw I’ll give brainlest
-Dominant- [34]

Answer:

20 percent

40 percent

20 percent

20(.008) percent

Step-by-step explanation:

6) 54 - 45 = 9

45 / 9 = 5

100 / 5 = 20

20 percent

7) 60 - 36 = 24

60 / 24 = 2.5

100 / 2.5 = 40

40 percent

8) 30 - 24 = 6

30 / 6 = 5

100 / 5 = 20

20 percent

9) 24.99 - 19.99 = 5

24.99 / 5 = 4.998

100 / 4.998 approx. = 20.008

20.008 percent (or rounded 20 percent)

4 0
2 years ago
A first alloy contains x pounds of 55% silver. It is mixed with a second alloy containing 30% silver to make 60 pounds of an all
Ann [662]

Answer:

"24 pounds" is the appropriate answer.

Step-by-step explanation:

According to the question, the equation will be:

⇒ x+y=60...(equation 1)

or,

⇒ \frac{55}{100}x+\frac{30}{100}y=\frac{40}{100}\times 60

      55x+30y=2400...(equation 2)

Now,

By multiplying (equation 1) by 55 and (equation 2) by 1, we get

⇒ 55x+55y=3300...(equation 3)

⇒ 55x+30y=2400...(equation 4)

From equation 3 and 4, we get

⇒ 25y=900

       y=\frac{900}{25}

          =36

By putting the values of "y" in equation 1, we get

⇒ x=60-36

       =24

Thus the value of x be "24 pounds".

3 0
3 years ago
out of 125 children at summer camp 45 signed up for swimming 38 for arts and crafts if a child is randomly selected what is the
anzhelika [568]
P(s) = 45/125 = 0.360
P(A&C) = 38/125 = 0.304
Probability that one is not in Arts and Crafts = 1- P(A&C) = 1-0.304 = 0.696

Therefore,
Probability that the child selected is in swimming when its known they didn't sign for Arts and craft = Probability they signed for swimming * Probability that they didn't sign for Arts and Crafts = 0.360*0.696 = 0.25056
3 0
4 years ago
Read 2 more answers
The procedure known as determines which digit at the right of the number will be the last digit displayed and increases it by on
Oduvanchick [21]
This procedure is known as estimating or rounding, where one compares the digit to the right is the number and sees whether or not is found within a given range, greater than 5 and can be used to increase the number in question, by a value of 1.
7 0
4 years ago
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