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Evgesh-ka [11]
3 years ago
5

Use the data in this stem-and-leaf plot to answer the question.

Mathematics
1 answer:
hram777 [196]3 years ago
6 0
There were 11 dogs in the sample
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The tables represent the functions f(x) and g(x).
dolphi86 [110]

A function assigns the values. The correct option is C, x=-6.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A.) When the value of x is -12,

f(-12) = 2/3(-12) + 7 = -1

g(-12) = 2(-12) + 15 = -9

B.) When the value of x is -9,

f(-9) = 2/3(-9) + 7 = 1

g(-9) = 2(-9) + 15 = -3

C.) When the value of x is -6,

f(-6) = 2/3(-6) + 7 = 3

g(-6) = 2(-6) + 15 = 3

D.) When the value of x is -3,

f(-9) = 2/3(-3) + 7 = 5

g(-9) = 2(-2) + 15 = 11

Hence, the correct option is C, x=-6.

Learn more about Function:

brainly.com/question/5245372

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4 0
2 years ago
How many three-letter sequences are possible that use the letters q,u,a,k,e,s at most once each?
Angelina_Jolie [31]
6P3 => 6!/(6-3)! = 120.

I can't very well explain, but I hope it works.
8 0
3 years ago
10.210 ÷ 10 (Long Division Work)
Anna [14]
1.0210 is the answer

hoped this helped
5 0
3 years ago
Read 2 more answers
A necklace usually sells for 18, but is onsale for 15% off. What is the sale price of the necklace?
I am Lyosha [343]

Answer:

15.3

Step-by-step explanation:

18-(18×(15%))= 15.3

6 0
2 years ago
Read 2 more answers
Please helppp with this math question &lt;333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

5 0
3 years ago
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