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choli [55]
3 years ago
13

What value of x would make Bl parallel to RA?

Mathematics
1 answer:
igomit [66]3 years ago
8 0

Given:

Bl parallel to RA.

To find:

The value of x.

Solution:

In triangle ATR and ITB,

\angle ATR\cong \angle ITB              [Common angles]

\angle ART\cong \angle IBT              [Corresponding angle]

\triangle ATR\sim \triangle ITB              [AA property of similarity]

We know that the corresponding sides of a similar triangle are proportional. So,

\dfrac{AT}{IT}=\dfrac{AR}{IB}

\dfrac{x}{x+8}=\dfrac{12}{18}

\dfrac{x}{x+8}=\dfrac{2}{3}

On cross multiplication, we get

3(x)=2(x+8)

3x=2x+16

3x-2x=16

x=16

Therefore, the correct option is C.

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Step-by-step explanation:

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3 years ago
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Question Number 2!! Thank youu
rewona [7]

Answer:

56°

Step-by-step explanation:

Since triangle ABD and triangle CBD are congruent (SAS), so you can divide m∠ABC by 2 to get the m∠ABD and m∠CBD, or 56°.

3 0
2 years ago
Miles had a piece of paper 1/4 of a large circle cut in three equal parts from the center point of the circle. What angle is the
telo118 [61]
The angle of 1/4 of a circle is given by:
 (1/4) * (360) = 90 degrees
 We now look for the angle that results from dividing 1/4 of a circle into three equal parts.
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3 years ago
Solve the simultaneous equations<br> 5y−4x=8<br> y+x=7<br><br> x= ?<br> y= ?
inna [77]

Answer:

x=3 y=4

Step-by-step explanation:

5(4)=20

4(3)= 12

20-12=8

4+3=7

4 0
3 years ago
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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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4 years ago
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