Quadrilateral EFGH is on a coordinate plane. Segment FG is on the line 3x − y = −2, and segment EH is on the 3x − y = −6. Which
1 answer:
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Answer:
C: (-8,3) R:5
Step-by-step explanation:
The equation of a circle can be written as:
(x-h)^2+(y-k)^2=r^2
where (h,k) is the center, and r is the radius
We have the equation:
(x+8)^2+(y-3)^2=25
Center:
The center is (-8,3)
(x+8)^2--> (x-h)^2
Therefore the x coordinate of the center is -8
(y-3)^2-->(y-k)^2
Therefore the y coordinate of the center is 3
Radius
r^2=25
Take the square root of both sides
r=5
Answer:
2nd graph (image)
Step-by-step explanation:
The function to graph is:
It follows the general pattern of the function: , which is general shape and in 1st and 3rd quadrants. So, we can eliminate 3rd and 4th choices (because of quadrants).
The answer is either 1st, or 2nd graph.
Now, we simply can check a point in both.
lets take x = 4, so the function would be:
f(4) = 4/4 = 1
Hence, point is:
(4,1)
The first graph doesn't go through this point. The second graph does.
hence, we can successfully choose the 2nd graph as our answer.