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Leno4ka [110]
3 years ago
12

(a) Write 0.7 as a percentage. (b) Write 43.2% as a decimal.help me​

Mathematics
2 answers:
Paraphin [41]3 years ago
6 0
(a) 0.7 as a percentage is 70%
melomori [17]3 years ago
4 0

Answer:

.7 into a percentage is 70 percent

and 43.2 as a decimal is .432

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7(z+2)-3z=44 quiero que me ayuden a resolver este problema por favor
slega [8]
No hablo expanol

7(z+2)-3z=44
7z+14-3z=44
7z-3z+14=44
4z+14=44
-14        -14
4z+14-14=44-14
4z+0=30
4z=30
1/4  1/4
(4z)/4=30/4
(4/4)z=15/2
1z=15/2
z=15/2



z=15/2
5 0
3 years ago
4y-8-2y+5=0 help please
tia_tia [17]
4y - 8 - 2y + 5 = 0
2y - 3 = 0
2y = 3
y = 3/2
4 0
3 years ago
Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

7 0
2 years ago
Given the figure below, find the values of x and z.
Lera25 [3.4K]

Answer:

z=98 and 5x+57 and z are supplementary.

Step-by-step explanation:

vertical angles theorem

5 0
3 years ago
Read 2 more answers
Please help me out please
AlexFokin [52]
Does not exist. The line would be vertical

7 0
2 years ago
Read 2 more answers
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