Ask question

Ask question

All categories

3 years ago

10

Hi, can you please do these? thanks for helping!

2 answers:

KATRIN_1 [288]3 years ago

5 0

Answer: (A) 1/10: 5 9/10 :5/6

(B) 3 3/4: -2 7/50

(C) 8 5/8 : 4/9

(D)2 2/5: 2 67/210: -2 2/3

(E)-1 1/2 : 81/128

Step-by-step explanation:

hopes this helps

arlik [135]3 years ago

4 0

Answer:

i will answer you other if u rate me brainliest

You might be interested in

PLEASE HELP ME WITH MATH PLEASE

Yuki888 [10]

Answer:

$a=250$

$b=10$

Step-by-step explanation:

$a=\frac{5x^2}{2}=\frac{5(10)^2}{2}=\frac{5(100)}{2}=\frac{500}{2}=250$

$b=\frac{2x^2(x-5)}{10x}=\frac{2(10)^2(10-5)}{10(10)}=\frac{2(100)(5)}{100}=2(5)=10$

7 0

2 years ago

Read 2 more answers

I Have A Comic Book That Has An Advertisement About Advanced Dungeons and Dragons, And I'm Considering Getting The Board Game An

stepan [7]

Answer:

You just play board game I will teach You What You dont know

5 0

3 years ago

Read 2 more answers

What is 48,100,000,000,000 in scientific notation? 4.81×10−11 4.81×10−13 4.81×1011 4.81×1013

SSSSS [86.1K]

Given number is 4,8100,000,000,000.

In this number of zero is 11. So we can write it as $481 * 10^{11}$

But for scientific notation we will enter decimal after two place in reverse direction.For this we will also multiply number by 10^2.

So number will be $4.81 * 10^{11} *10^2 = 4.81 * 10^{13}$

So fourth option is correct.

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

A skateboarder leaves a 12-foot tall ramp with an initial vertical velocity of 8 feet per sen

taurus [48]

To answer this, we substitute 12 ft to the f(h) in the given equation,
f(h) = -8t² + 8t + 12 = 12

Subtracting 12 from both sides of the equation will give us an answer of,

-8t² + 8t = 0

Then, we transpose 8 to the other side and divide the equation by -8 and t, we get an answer of t = 1 second.

7 0

1 year ago

Read 2 more answers