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Sonbull [250]
4 years ago
10

Hi, can you please do these? thanks for helping!​

Mathematics
2 answers:
KATRIN_1 [288]4 years ago
5 0

Answer: (A) 1/10: 5 9/10 :5/6

(B) 3 3/4: -2 7/50

(C) 8 5/8 : 4/9

(D)2 2/5: 2 67/210: -2 2/3

(E)-1 1/2 : 81/128

Step-by-step explanation:

hopes this helps

arlik [135]4 years ago
4 0

Answer:

i will answer you other if u rate me brainliest

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Read 2 more answers
MATH PROBLEM!! PLEASE HELP!! <br>Explain your answer please
love history [14]
<h3>Answer:  angle B = 47 degrees</h3>

========================================

Work Shown:

Use law of cosines to find angle B

b^2 = a^2 + c^2 - 2*a*c*cos(B)

9^2 = 6^2 + 12^2 - 2*6*12*cos(B)

81 = 36 + 144 - 144*cos(B)

81 = 180 - 144*cos(B)

81 - 180  = -144*cos(B)

-99  = -144*cos(B)

-144*cos(B) = -99

cos(B) = (-99)/(-144)

cos(B) = 0.6875

B = arccos(0.6875)

B = 46.5674634422102

B = 47 when rounding to the nearest whole number

Make sure your calculator is in degree mode.

arccos is the same as inverse cosine often labeled \cos^{-1} on calculators.

5 0
3 years ago
Write this as an equation in point-slope form Please answer as quickly as possible. 50 pts!!!!!
jeka57 [31]

The answer is:   "  y − 1  =  - 3(x + 2) " .
__________________________________________________________

Explanations: 
__________________________________________________________

<u>Note</u>:  The "point-slope form" of the equation of a line is:

                  →     " y − y₁ = m(x −x₁) " . 

We are given the slope,  m" , is:  " - 3 " ;  

We are given a point on the line [on the graph that is represented by this equation];  with the coordinates:  " (-2 , 1) " ;  

                          →   which is in the format: " (x₁ , y₁) " ;
                                      
                          →   As such:  " x₁  = -2 "  ;   " y₁  =  1 " ; 
_____________________________________________________
As aforementioned, the equation of a line in "point-slope form" ;  is:  
_________________________________________________________
                          →    " y − y₁ = m(x − x₁) " ;  

in which:
 
 →  "(x₁ , y₁) " represents the coordinates of a given point on the [line of the graph represented by the equation] ;  AND: 

 →   " m "  =   the slope of the line [represented by the equation] " ; 

We proceed by substituting our known values for "m" ;  "y₁" ; and "x₁" :
 
 →       " y − 1  =  - 3(x − (-2) ) "  ;   
_______________________________________________________                                                        
 →   Rewrite as:
_______________________________________________________
 →      "  y − 1  =  - 3(x + 2) "  ;  

 →    which is our answer;  since it is written in "point-slope form" .
_______________________________________________________
3 0
3 years ago
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