Answer:
You have to do that on your computer not someone elses....
Explanation: you have to do it
Answer: Recommend solutions to problems & Analyze information and problems.
A business analyst is a person that takes a look at a company's current system and tries to understand how the company works. These analyst seek to find out how the company will be in the future. Their main job is actually to oversee the different projects done by the company and analyze the different projects to determine if it would benefit the company or not.
Since business analysts thrive to understand their company's system, they are often the people who find information and problems that the company may have in the present or in the near future. These workers also recommend solution to problems that the company may have. The analysts are also often working with the IT departments of companies to help with the moving forward of the company's current system.
Answer:
#include<stdio.h>
#include <iostream>
using namespace std;
int main(){
int number, min, max;
cout << "Enter the minimum range: ";
cin >> min;
cout << "Enter the maximum range: ";
cin >> max;
cout << "Odd numbers in given range are: ";
for(number = min; number <= max; number++)
if(number % 2 !=0)
cout << number<< " ";
cout<< "Even numbers in given range are: ";
for(number = min; number <= max; number++)
if(number % 2 ==0)
cout << number << " ";
return 0;
}
Explanation:
First of all, we take declare two variables. one as the lowest number of the range and the other as the upper limit of the range (in this case: <em>min</em> and <em>max</em>). We declare another variable (<em>number</em>) and store in it the lowest number of the range (<em>min</em>). To check whether the number currently stored as the value of the variable (<em>number</em>) is even, we take in account the remainder of that number divided by 2. If the remainder does not equals 0, we print that number as odd. We again check the remainder by dividing the number by 2. If the remainder does equals 0, we print that number as even.
Answer:
shvet putra kaa Sam's vigrah hai.
Answer:
Here is the code for a classic C++ program that does it:
--------------------------------------------------------------------------------
#include <iostream>
using namespace std;
int main()
{
int sum = 0;
int n;
cout << "Input 10 numbers: " << endl;
for (int i = 0; i < 10; i++)
{
cin >> n;
sum += n;
}
cout << "Sum of the numbers: " << sum << endl;
}
--------------------------------------------------------------------------------
Explanation:
I'm assuming you know what "include", "using namespace std" and "int main()" do, so I will skip over those.
First, we declare a variable "sum" and initialize it with 0 so we can add numbers to it later.
Then, we declare a variable "n" that will be set as the input of the user.
The "for-loop" will iterate ( go ) from 0 to 9, and will set the value of "n" as the input that is given -> "cin >> n;". After that, we add the value of "n" to the sum variable.
After "i" reaches 9, it will exit the loop and proceed to printing the sum of the numbers.
Hope it helped!
