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EleoNora [17]
3 years ago
8

Simplify the expression:

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

1. -b^2+13b

2. 1.9y^2-1.4y+4

Step-by-step explanation:

1. -0.8b^2+7.4b+(5.6b-0.2b^2)

Simplify: -0.8b^2+7.4b+5.6b-0.2b^2

Add like terms: (-0.8b^2-0.2b^2)= -1b^2/-b^2 (7.4b+5.6b)= 13b

Answer: -b^2+13b

2. (7.3y-y^2+4)+0.5y^2-(8.7y-2.4y^2)

Simplify: 7.3y-y^2+4+0.5y^2-8.7y+2.4y^2

Add like terms: (2.4y^2-y^2)= 1.9y^2 (7.3y-8.7y)= -1.4y (don't forget about the 4)

Answer: 1.9y^2-1.4y+4

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Step-by-step explanation:

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4 0
3 years ago
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If (cos)x= 1/2 what is sin(x) and tan(x)? Explain your steps in complete sentences.
Natasha_Volkova [10]
The correct answers are:
1) sin(x) = \frac{ \sqrt{3} }{2}
2) tan(x) = \sqrt{3}

Explanation:
Given:
cos(x) =  \frac{1}{2}

Step 1:
Since, according to the Trigonometric identity:
sin^2(x) + cos^2(x) = 1 -- (1)

Step 2:
Plug in the value of cos(x) in equation (1):
sin^2(x) + ( \frac{1}{2} )^2 = 1 \\ sin^2(x) + \frac{1}{4} = 1 \\ sin^2(x)  =  \frac{3}{4}

Step 3:
Take square-root on both sides:
\sqrt{sin^2(x)} =  \sqrt{\frac{3}{4}}

sin(x) = \frac{ \sqrt{3} }{2}

Now to find the tan(x), we would use the following formula:

tan(x) = \frac{sin(x)}{cos(x)} --- (2)

Plug in the values of sin(x) and cos(x) in equation (2):
tan(x) = \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} }

Hence tan(x) = \sqrt{3}
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3 years ago
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