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3 years ago

Help me plssssss i don’t know how to do this

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

Answer:

AC = $\sqrt{15}$

Step-by-step explanation:

Assuming you require AC

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

AC² + BC²= AB²

AC² + 7² = 8²

AC² + 49 = 64 ( subtract 49 from both sides )

AC² = 15 ( take square root of both sides )

AC = $\sqrt{15}$ ≈ 3.87 ( to 2 dec. places )

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I need help please slope

loris [4]

Answer:

Step-by-step explanation:

The formula for slope is y2-y1/x2-x1 where y2 and x2 are the x and y coordinates from a coordinate pair and y1 and x1 are the coordinates from another coordinate pair. In this case, 2 coordinate pairs are given: (30,75) and (10, 35) 75-35/30-10 would be your slope, or, 40/20, or simplified, 2.

Your slope is 2

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3 years ago

How do you multiple 783 by 42 in area model

BigorU [14]

Answer: this depends are you finding it for a shape or in general if it is in general you simply multiply and get 32,886

Step-by-step explanation:

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4 years ago

In a rhombus CROW...

Montano1993 [528]

<h2><u>Rhombus</u></h2>

<h3>In a rhombus CROW...</h3>

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2 years ago

Solve the equation for all real solutions in simplest form.<br> z^2 - 12z +9= -3

Mars2501 [29]

Answer:

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$

First simplifying the equation:

$z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0$

Now, we can solve the equation using quadratic formula:

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

we have a = 1, b=-12 and c=12

Putting values in formula and finding values of x

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\z=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(12)}}{2(1)}\\z=\frac{12\pm\sqrt{144-48}}{2}\\z=\frac{12\pm\sqrt{96}}{2}\\z=\frac{12\pm9.8}{2}\\z=\frac{12+9.8}{2}\:or\:z=\frac{12-9.8}{2}\\z=10.9\:or\:z=1.1$

So, we get value of z: z=10.9 or z=1.1

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

3 0

3 years ago

The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula

ryzh [129]

Answer:

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

Step-by-step explanation:

We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.5 = 0.9$ , so $z = 1.282$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.282*\frac{6}{\sqrt{21}} = 1.68$

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.

The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

6 0

3 years ago