Answer: ∠ACB= 60°, ∠DCE= 65°, ∠BCD= 55°
Step-by-step explanation:
1) Since ΔABC is an equilateral, we know ∠ACB= 60°
2) Since we know ΔCDE is an isosceles, we know that ∠DCE= 1/2 (180-50), which is 65°
3) We can add the 2 angles and then subtract them from 180 degrees to get ∠BCD= 55°
The area of a square is:
A=s^2, solve this for s
s=√A
The "diagonal" is the hypotenuse of a right triangle with legs of length s.
By the Pythagorean Theorem:
d=√(s^2+s^2)
d=√(2s^2), and since we found that s=√A earlier:
d=√(2A), and since we are told that A=128m^2
d=√256
d=16m
Answer:
x=8.2
Step-by-step explanation:
6.7x=5.2x+12.3
subtract 5.2x from 6.7x
1.5x=12.3
divide 1.5 by 12.3 to get x alone
x=8.2
That would be 49 because AB is basically LM and AC is basically LN. Also 5 (AB) times 7 equals 35 (LM), which means 7 (AC) times 7 equals 49 (LN) which is LN. Hope I helped!!