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3 years ago

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is nine

2 answers:

6 0

Divide the measure of all 3 angles into 10 parts...1 part is the measure of angle x, and the other angles add up to the other 9 parts. 180/10=18...so x = 18.
So angle y and z together add up to the other 162 degrees.
Divide 162 in half to find the “middle”...162/2=81.
Since we were told that the difference between y and z is 20...y would be 10 less than that middle number, and z would be 10 more than it...so y=71, and z=91.
The answers are...
X=18, Y =71, Z=91

UkoKoshka [18]3 years ago

4 0

Yea I agree that the correct answer
Ok

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A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de

gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y = the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

#SPJ4

4 0

1 year ago

In ΔABC, BC = 4 centimeters, m∠B = m∠C, and m∠A = 20°. What is AC to two decimal places?

ipn [44]

M<A = 20°
m0°

Law of Sines , in any triangle we have
a/sin A = b/sin B = c/sin c

4/sin20 = AC/sin80 = AB/sin80

now we can solve AC

4/sin20 = AC/sin80
AC = 4 (sin80)/ sin20
AC = 4(0.98) / (0.34)
AC = 3.92 / 0.34
AC = 11.52

answer

C.11.52 centimeters

5 0

3 years ago

Read 2 more answers

Una empresa fabrica dos productos, X y Y. Cada cantidad del articulo X producida requiere dos horas de trabajo en una taladrador

Zarrin [17]

Answer:

la respuesta esta abajo

Step-by-step explanation:

a) Sea x el número del artículo x mientras que y representa el número del artículo y.

Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:

2x + 5y ≤ 40

b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.

c) Para 10 unidades de X y 5 unidades de y:

2 (10) + 5 (5) = 45> 40

Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.

8 0

3 years ago

Recognize whether the fractions are Cleveland right yes Arnel use fraction tiles or number lines

wolverine [178]

1. No sorry I just know #1

7 0

3 years ago

Please help ASAP. Thanks so much.

MAVERICK [17]

Answer:

B. 3

Step-by-step explanation:

To find the value of c, substitute the x and y values of the given point into x and y of the equation, then isolate c. Since that given point is (2,5), substitute 2 for x and 5 for y:

$(5) = -2(2)^2+8(2)-c\\5 = -2(4)+16-c\\5 = -8 + 16 - c \\5 = 8 -c\\-3 = -c\\c = 3$

Thus, c = 3.

5 0

3 years ago