Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
Step-by-step explanation:
0.75a + 2(0.90) = 27.60
is the correct answer
3x+15x = 180
18x = 180
x = 10
10(x+y) + 3x = 180
10x + 10y + 3x = 180
13x + 10y = 180
13(10) + 10y = 180
130 + 10y = 180
10y = 50
y = 5
Answer:
Step-by-step explanation:
<u>Simplify:</u>
- √5(√8 + √18) =
- √5*8 + √5*18 =
- √40 + √90 =
- √4*10 + √9*10 =
- 2√10 + 3√10 =
- (2 + 3)√10 =
- 5√10
<u>The value of a:</u>
Answer:
don't know it sorry about tht