Let's find the expressions for the length and width of the rectangle. The length (which we will call <em>l</em>) is 2 units less than some undefined number, thus we will use the variable <em>x</em>:
l = x - 2
The width is 4 more than this length:
w = l + 4 = (x - 2) + 4 = x + 2
Now, given that we have the length and width and are looking for the area, we need to multiply these expressions together.
One way to write this would simply be (x + 2)(x - 2). If we wanted to find a different way of writing the area, we could use FOIL to find all terms and get x^2 - 4.
The distance between the two points is 20
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:2
5x^2-1
Step-by-step explanation:
