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Alexxx [7]
3 years ago
11

Find the solution set of the inequality

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0

<u>Answer:</u>

\boxed{\textsf{ Hence the solution set is$ \bf{\bigg( \dfrac{33}{4},\infty \bigg) }$}}.

<u>Step-by-step explanation:</u>

A inequality is given to us and we need to find the solution set. So the given inequality to us is ,

  • -4x + 35 >2

\bf\implies -4x + 35 > 2 \\\\\bf\implies -4x > 2-35 \\\\\bf \implies -4x > -33 \\\\\bf \implies x >\dfrac{-33}{-4}\\\\\bf \implies x > \dfrac{33}{4} \\\\\bf\implies \boxed{\pink{\bf x \in \bigg(\dfrac{33}{4}, \infty \bigg) }}

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
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How can I solve 2t+4w=6 + 4t +6w= 15 using elimination?
xeze [42]
I hope this helps you



-2/2t+4w=6


-4t-8w= -12


4t+6w=15


-2w=3


w= -3/2


2t-4.3/2=6


2t=12


t=6
3 0
3 years ago
I need help!! please, you don’t even have to do it all just explain to me how to do the first one I’ll catch on
lisov135 [29]

Hi there!

<u>What we need to know:</u>

The three main trigonometric ratios are sine, cosine and tangent:

\displaystyle sin\theta=\frac{opposite}{hypotenuse}     \displaystyle cos\theta=\frac{adjacent}{hypotenuse}    \displaystyle tan\theta=\frac{opposite}{adjacent}

"Opposite" refers to the side opposite the angle that is not the hypotenuse.

"Hypotenuse" refers to the side opposite the right angle of a right triangle.

"Adjacent" refers to the side next to the angle that is not the hypotenuse.

"θ" is read as "theta". It just represents the angle.

Keep in mind that these three ratios only apply to right triangles.

You can use the mnemonic "soh-cah-toa" to help you remember these ratios.

<u>First question</u>

For the first question, we're given the angle with a measure of 56 degrees and the length of the <em>hypotenuse</em>. We must calculate <em>a</em>, which represents the side <em>adjacent </em>to the given angle.

Given the hypotenuse and the adjacent side, we know that we must use the cosine ratio:

\displaystyle cos\theta=\frac{adjacent}{hypotenuse}

Plug in the given information:

\displaystyle cos56=\frac{a}{13}

Isolate <em>a</em> by multiplying both sides by 13:

13\displaystyle cos56=a

Solve using a calculator:

a=7.3

Therefore, <em>a</em> is equal to 7.3 when rounded to 1 decimal place.

<u>Other information you will need to know:</u>

In the above question, we needed to solve for a side. But what if we were given two sides and we needed to solve for an angle? For example:

\displaystyle sin\theta=\frac{5}{8}

In this case, we will use the inverse sine ratio:

\displaystyle \theta=sin^-^1(\frac{5}{8})

Solve using a calculator:

\displaystyle \theta=39

Therefore, the angle would equal approximately 39 degrees.

I hope this helps!

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