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GalinKa [24]
3 years ago
6

Consider the expression 625(5xy)^-3/ (5x)^2 y^7

Mathematics
1 answer:
andre [41]3 years ago
3 0
<span>625(5xy)^-3/ (5x)^2 y^7
     
             625 
= --------------------   /  25x^2y^7
      125 x^3y^3

= 5/x^3y^3    / </span>25x^2y^7
= 5/x^3y^3   *  (1/ 25x^2y^7)
= 1 / 5x^5y^10

answer


         1
-----------------
   5x^5y^10
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(x - 5) + (x - 1)<br> Simplify
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x-5+x-1x−5+x−1

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3 years ago
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Peter can buy 5 juice bottles for $10 or 6 juice bottles for $12. How much do you think he would pay for 7 juice bottles?
yuradex [85]
He would pay $14. Each juice bottle costs $2, so 7 bottles cost $14. 
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3 years ago
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If 1/4 of the 7th graders got an A on the test and 2/5 of them got a B, that fraction of the students got an A or B?
posledela

Answer: \dfrac{13}{20}

Step-by-step explanation:

Given: Fraction of 7th graders got A = \dfrac14

Fraction of 7th graders got B = \dfrac25

The fraction of the students got an A or B = Fraction of 7th graders got  + Fraction of 7th graders got B

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5 0
3 years ago
What are the roots of the equation?<br><br> x^2+24=−11x<br><br> Enter your answers in the boxes.
docker41 [41]
<span>The <u>correct answers</u> are:

x=-3 and x=-8.

Explanation<span>:

We can first write this in standard form, ax</span></span>²<span><span>+bx+c=0. To do this, we will add 11x to both sides:
x</span></span>²<span><span>+24+11x=-11x+11x
x</span></span>²<span><span>+11x+24=0.

Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).

The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.

Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.

Solving the first equation:
x+3-3=0-3
x=-3.

Solving the second equation:
x+8-8=0-8
x=-8.</span></span>
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3 years ago
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