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3 years ago

The interior angles of regular polygon is given below. calculate the number of sides the polygon has .

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

Answer. Each interior angle of the polygon is 108 degrees, so each exterior angle of the polygon is 180-108 = 72 degrees. So the number of sides is 360/72 = 5. Hence it is a regular pentagon.

Step-by-step explanation:

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The times of the runners in a marathon are normally distributed, with a mean of 3 hours and 50 minutes and a standard deviation

balu736 [363]

Answer: 0.16

Step-by-step explanation:

Given that the run times provided are normally distributed ;

Mean(x) of distribution = 3 hours 50 minutes

Standard deviation(s) = 30 minutes

The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes

3 hours 20 minutes = (3 hrs 50 mins - 30 mins):

This is equivalent to :

[mean(x) - 1 standard deviation]

z 1 standard deviation within the mean = 0.84

z, 1 standard deviation outside the mean equals:

P(1 - z value , 1standard deviation within the mean)

1 - 0.8413 = 0.1587

= 0.16

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3 years ago

TanA+tan(60+A)+tan(120-A)=3tan3A

Volgvan

Answer: not and identity

Step-by-step explanation:

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3 years ago

What is the simplified form of left parenthesis 27 x to the power of negative six end power y to the power of 12 end power right

Tanzania [10]

Hello,
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3 years ago

WILL GIVE BRAINLIEST !!!

wel

Answer:

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Step-by-step explanation:

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3 years ago

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

3 years ago