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kicyunya [14]
2 years ago
10

What's the equation of this table

Mathematics
2 answers:
Aneli [31]2 years ago
8 0

Answer:

y = 4.5x + 8.5

Step-by-step explanation:

this is true

Sonja [21]2 years ago
8 0
The answer is 4.5+8.5.
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Show by substitution whether the number r is a solution of the corresponding quadratic equation.
Stels [109]

Answer:

It's choice B.

Step-by-step explanation:

When r= -11,

x^2 + 8x - 33 =  (-11)^2 - 88 - 33

= 121 - 88 - 33

= 0

- so x = -11 gives a zero value and is a solution to the equation.

3 0
2 years ago
Question 1 (Essay Worth 10 points)
zysi [14]

$394.51 is future value of money after 2 years.

What future value means?

  • A current asset's future value (FV), which is based on an estimated rate of growth, is its value at a later time.
  • Investors and financial planners use the future value to project how much an investment made now will be worth in the future.

The method that results in more money after 2 years is Peggy's investment.

Which method results in more money in 2 years?

The formula for calculating the future value of an investment:

FV = P (1 + r)^nm

FV = Future value

P = Present value

R = interest rate

m = number of compounding

N = number of years

Future value of Larry's investment: $350 x [1 + (0.04/4)]^(4 x 2) = $379

Future value of Peggy's investment: $350 x [1 + (0.06/12)]^(12 x 2) = $394.51

Learn more about future value

brainly.com/question/14860893

#SPJ13

4 0
1 year ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
A carpenter wants to make sure that the corner of a triangular frame he is building is a right angle. If he measures two sides o
Mama L [17]
13 feet
Pythagorus is used
25 + 144 = 169
169 is 13 to the second power etc
6 0
1 year ago
I'm not sure can someone help me !!!
xz_007 [3.2K]
Turn it into transcript, It's upside down and I can't see it properly.
7 0
2 years ago
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