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grin007 [14]
3 years ago
13

What is the quotient of 3/4 and 5/6

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

9/10

Step-by-step explanation:

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Please answer it now in two minutes
Maurinko [17]

Answer:

17.5

Step-by-step explanation:

27+4x+8=6x

27+8=6x-4x

35=2x

x=35/2=17.5

8 0
3 years ago
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How many times does 4 go in 64
Afina-wow [57]

Answer:

Step-by-step explanation:

4 goes into 64 sixteen times. 64/4 = 16 16 x 4 = 64

7 0
3 years ago
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Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50
VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

\texttt{ }

<em>Jaces songs were played on 6 more commercials than movies.</em>

\boxed{C = 6 + M} → <em>Equation 1</em>

\texttt{ }

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

\boxed{50C + 140M = 680} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1  ↔ Equation 2 :</em>

50C + 140M = 680

50 ( 6 + M ) + 140M = 680

300 + 50M + 140M = 680

190M = 680 - 300

190M = 380

M = 380 \div 190

M = 2

\texttt{ }

C = 6 + M

C = 6 + 2

C = 8

\texttt{ }

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0
3 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Which number has a prime factorization of 2x2x5x5x7x7
Dominik [7]

Answer:

4900

Step-by-step explanation:

multiply all those numbers together

2x2x5x5x7x7 = 4900

6 0
3 years ago
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