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3241004551 [841]
3 years ago
8

A bag contains 150 marbles. Some are blue, and the rest are white. There are 21 blue marbles for every 4 white marbles. . How ma

ny blue marbles are in the bag
Mathematics
2 answers:
Monica [59]3 years ago
5 0
There are 84 blue marbles in the bag
fiasKO [112]3 years ago
4 0
If goal to get white marble then 16 if goal to get blue marbles then its 84

BRAINLIEST APPERICATED :D
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1 over 5a to the 2nd power
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3 years ago
One function of a movie projector is to enlarge the image on the film. This procedure is an example of a
eimsori [14]

Answer:

dilation

Step-by-step explanation:

dilation

4 0
3 years ago
Compare and contrast the solution of a-3=15 and a-3 is greater than or equal to 15.
aivan3 [116]
In a - 3 = 15, the value of a HAS to be 18.

In a - 3 is greater than or equal to 15, the value of a is any value that is 18 or higher.
7 0
3 years ago
R , S, and T are the vertices of one triangle. E, F, and D are the vertices of another triangle. mR = 60, mS = 80, mF = 60, mD =
Mumz [18]

Answer:

Yes, the two triangles are congruent, by ASA.

Step-by-step explanation:

In order to find if two triangles are congruent, you need the information of at least three out of the six incongnits of a triangle (the incognits are the three sides and the three angles)

Some of the ways to know if they're congruents are:

-ASA (Angle, side, angle): Two angles and the included side are equal for both triangles.

-AAS(Angle, angle, side): Two angles and a non-incuded side are equal for both triangles

-SAS(Side, angle, side): Two sides and the included angle are equal for both triangles.

In this case, two angles and one side of each triangle are known.

For the triangle RST, you know two angles and the included side.

For the triangle EFD, you know two angles and the non-included side. But is also known that the sum of the angles of a triangle is 180°, therefore you can obtain the third angle of EFD:

180=m∡F+m∡D+m∡E

m∡E= 180 - 60 -40

m∡E= 80°

Therefore:

m∡E=m∡S

m∡F=m∡R

RS=EF

Hence, two angles and the included side for RST and EFD are equal and the triangles are congruent by ASA.

8 0
3 years ago
Determine the area of each polygon below <br><br> Help me please
julia-pushkina [17]
9) Separate the polygon into 2 shapes (a rectangle and triangle). Then plug in the formula for those 2 shapes separately and add the 2 areas.
First, the triangle's area = bh x 1/2 or bh/2.
b=5 and h=5, so 5x5/2 or 25/2 = 12.5.
Next, solve the area for the rectangle(lw=A). l=5 and 2=8, so 5x8=40.
Add 40 +12.5 = 52.5cm^2 (always include units).

10) It is similar to the last problem. You will separate the polygon into 2 shapes (a circle and a square), but this time you will subtract the area of the sector formed from the circle (draw a dotted line where the circle would be formed in the square).
So, the area of the square is 2x2=4ft^2. 
area of a circle is (pi)r2 or (pi)2^2= 4pi or about 12.5ft^2.
4+12.5 = 16.5 ft^2.
Now, the area of the sector must be subtracted from the combination of the 2 areas found above.
The area of a sector is 2(pi)r x (C/360).
The angle is given as 90°, the radius is 2 ft. Now plug these into the equation.
2(pi)(2)x(90/360) = 3.14ft^2.
16.5-3.14= 13.4 ft^2.

6 0
3 years ago
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