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Strike441 [17]
3 years ago
10

How many ounces of a silver alloy that costs $5.50 per ounce should be mixed with one that costs $7.00 per ounce to make a new 3

0 ounce alloy that costs $6.40 per ounce?
Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

<u>135.73 ounces</u> of a silver alloy that costs $5.50 per ounce should be mixed.

Step-by-step explanation:

Given:

A silver alloy that costs $5.50 per ounce should be mixed with one that costs $7.00 per ounce to make a new 30 ounce alloy that costs $6.40 per ounce.

Now, to find the ounces of silver alloy.

Let the silver costs $5.50 per ounce be x.

And the silver costs $7.00 per ounce be y.

So, the total ounce make a new alloy:

x+y=30\\y=30-x  ....(1)

Now, the total costs of silver alloy:

5.50x+7y=6.4

Putting the value of y from equation (1) in the place of y :

5.50x+7(30-x)=6.4

5.50x+210-7x=6.4

-1.5x+210=6.4

<em>Subtracting both sides by 210 we get:</em>

-1.5x=-203.6

<em>Dividing both sides by -1.5 we get:</em>

x=135.73

Therefore, 135.73 ounces of a silver alloy that costs $5.50 per ounce should be mixed.

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