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Salsk061 [2.6K]
3 years ago
9

In the image above x=11 cm. Find the surface area of the figure.

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

726

Step-by-step explanation:

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Answer:

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the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

<u>Step-by-step explanation:</u>

Here we have , to find  the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake . Let's find out:

We know that , Value of earthquake is given by formula

⇒ M = Log(\frac{I_1}{I_0} ) , Where M is magnitude of earthquake

I_1  is the measured magnitude of intensity of  earthquake .

I_0  is the standard magnitude of intensity of  earthquake .

According to question , I_1 = 5011I_0 , Hence

⇒ M = Log(\frac{I_1}{I_0} )

⇒ M = Log(\frac{5011(I_0)}{I_0} )

⇒ M = Log(5011 )

⇒ M =3.69924    { On rounding off we get }

⇒ M =3.7

Therefore , the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

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We are given that 24 out of 36 inches of ribbon is used. The percentage that is used is equivalent to:

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