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Lelechka [254]
3 years ago
14

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=71°, and RS = 2.5 feet. Find the length of SQ to the nearest tenth of a foot

Mathematics
2 answers:
Leto [7]3 years ago
7 0

Answer:

Answer is in the picture

ArbitrLikvidat [17]3 years ago
3 0

Answer: 0.9

tan71=

x

2.5

​

x\tan 71=2.5

xtan71=2.5

\frac{x\tan 71}{\tan 71}=\frac{2.5}{\tan 71}

tan71

xtan71

​

=

tan71

2.5

​

x=\frac{2.5}{\tan 71}=0.8608\approx 0.9\text{ feet}

x=

tan71

2.5

​

=0.8608≈0.9 feet

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stiks02 [169]
"0.5 ft * 12 = 6 inches (because there are 12 inches in 1 foot)1 day = 24 hours0.5 ft per day = 6 inches in 24 hoursInches grown in one hour = 6/24 = 0.25"
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3 years ago
Could someone please explain how to get the answer?
MaRussiya [10]

the missing side of the right triangle is 10.568

<h3>Pythagorean theorem formula</h3>

a² + b² = c²

<em>Which c is the hypotenuse part of triangle.</em>

<h3>Known that </h3>

a = 5.2

b = 9.2

c = ...?

<em>so</em><em> </em><em>the</em><em> </em><em>missing</em><em> </em><em>part</em><em> </em><em>is</em><em> </em><em>c</em><em>.</em>

<h3>Way to calculate</h3>

a² + b² = c²

5.2² + 9.2² = c²

111.8 = c²

c = √111.8

c = 10.568

#Moderators please don't be mean, dont delete my answers just to get approval from your senior or just to get the biggest moderation daily rank.

7 0
3 years ago
25h to the power of 10 +18
lesya692 [45]

Answer:

1.509909034 x10 ^36

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6 0
3 years ago
Divide -20.40 and -4
MaRussiya [10]
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3 0
3 years ago
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The m
svp [43]

Answer:

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

Step-by-step explanation:

As we suspect the variability of concentration F - test is applied.

n1=10    s1=4.7

n2=16      s2=5.8

And α = 0.05.

The null and alternate hypothesis are

H0: σ₁²=σ₂²       Ha:  σ₁²≠σ₂²

The null hypothesis is  the variability in concentration does not  differ for the two companies.

against the claim

the variability in concentration may differ for the two companies

The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12

and 1/F∝(υ1,υ2) = 1/3.77= 0.26533

where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15

Test Statistic

F = s₁²/s₂²

F= 4.7²/5.8²=0.6566

Conclusion :

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

3 0
3 years ago
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