Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
.
To find:
The 
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]
In triangle AOB,
Therefore, the measure of angle AOB is 120 degrees.
Answer:
27
Step-by-step explanation:
Substitute x = 3 into the expression
2(3)² + 3(3) = 2(9) + 9 = 18 + 9 = 27
Answer:
726.572699
Step-by-step explanation:
According to differentials
(x+Δx)³ = x³ + 3x²Δx + 3x(Δx)² + (Δx)³ (Using binomial expansion)
Using this formula to solve (8.99)³, this can also be written as;
(8.99)³ = (9-0.01)³ where
x = 9
Δx = -0.01
Substitute this vales into the differential expression above
(9+(-0.01))³ = 9³ + 3(9)²(-0.01) + 3(9)(-0.01)² + (-0.01)³
(9+(-0.01))³ = 729 + (243)(-0.01) + 27(0.0001) + (-0.000001)
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 726.572699
Hence 8.99³ = 726.572699 (Using differential)
Using calculator;
8.99³ = 726.572699
It's 21.125 hope this works good luck ;)
