If EH = 9 and GH = 15, what is FH? Round your answer to the nearest tenth.

Malik's arts and crafts shop has a bolt of crimson velvet 32 meters long. A customer came in during the morning and bought 120 c

valkas [14]

Given:

Malik's arts and crafts shop has a bolt of crimson velvet 32 meters long.

Velvet purchased by first customer = 120 centimeters

Velvet purchased by second customer = 14 meters

To find:

The remaining velvet in Malik's shop.

Solution:

We know that,

1 meter = 100 cm

Using this conversion, we get

32 meter = 3200 cm

14 meter = 1400 cm

Now,

Remaining velvet in Malik's shop = (3200 - 120 - 1400) cm

= 1680 cm

Therefore, the remaining velvet in Malik's shop is 1680 cm.

3 0

3 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured parallel to a line

Ber [7]

Answer:

The distance is:

$\displaystyle\frac{3\sqrt{142}}{10}$

Step-by-step explanation:

We re-write the equation of the line in the format:

$\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}}$

Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.

In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:

$\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right>$

Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:

$x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t$

We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:

$\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3$

Then we solve that equation for t, to get:

$\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}$

Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:

$\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}$

Then to find the distance we just use the distance formula:

$\displaystyle d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

So we get:

$\displaystyle d=\sqrt{\left(-2-\frac{7}{10}\right)^2+\left(3-\frac{24}{5}\right)^2+\left(-4 +\frac{5}{2}\right)^2}=\frac{3\sqrt{142}}{10}$

3 0

3 years ago

Simplify;<br> (√3 + √2) (√3 + √2)

Marat540 [252]

Answer:

5 + 2√6 or 9.898979

Step-by-step explanation:

(√3 + √2) (√3 + √2)

= 5 + 2√6

decimal = 9.898979

6 0

3 years ago

Read 2 more answers

Please help me!!<br> 2(5– x)3 – 11=151

konstantin123 [22]

Answer:

x = -22

Step-by-step explanation:

2(5– x)3 – 11 = 151

(10 - 2x)3 - 11 = 151

30 - 6x = 162

-6x = 132

x = -22

5 0

3 years ago

Mike drew a quadrilateral with four right angles. What shape could be drawn?

Darya [45]

There could be 2 possible shapes that could’ve been drawn.

A rectangle, or a square.

All of their angles are 90° angles, which are right angles.

Hope this helped!

5 0

3 years ago