By my calculations and understanding into this problem I have figured out the answer to this thing and it is very simple and easy enough to actually say it so I can type it out instead because I can’t say anything on this thing even though I’m doing a voice record and I don’t even know how my grandma is doing right now so I’m just blah bling around is it random words of mine but honestly I would love to explain and tell you the answer but I do not know how to type it out so I’m just going to say it like I just said two seconds ago but I didn’t really say it again I just typed it I don’t know I keep getting confused with that but anyways the answer is very easy
Answer:r'=0.327 m
Step-by-step explanation:
Given
![N=2.85 rev/s](https://tex.z-dn.net/?f=N%3D2.85%20rev%2Fs)
angular velocity ![\omega =2\pi N=17.90 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20N%3D17.90%20rad%2Fs)
mass of objects ![m=1.5 kg](https://tex.z-dn.net/?f=m%3D1.5%20kg)
distance of objects from stool ![r_1=0.789 m](https://tex.z-dn.net/?f=r_1%3D0.789%20m)
Combined moment of inertia of stool and student ![=5.53 kg.m^2](https://tex.z-dn.net/?f=%3D5.53%20kg.m%5E2)
Now student pull off his hands so as to increase its speed to 3.60 rev/s
![\omega _2=2\pi N_2](https://tex.z-dn.net/?f=%5Comega%20_2%3D2%5Cpi%20N_2)
![\omega _2=2\pi 3.6=22.62 rad/s](https://tex.z-dn.net/?f=%5Comega%20_2%3D2%5Cpi%203.6%3D22.62%20rad%2Fs)
Initial moment of inertia of two masses ![I_0=2mr_^2](https://tex.z-dn.net/?f=I_0%3D2mr_%5E2)
![I_0=2\times 1.5\times (0.789)^2=1.867](https://tex.z-dn.net/?f=I_0%3D2%5Ctimes%201.5%5Ctimes%20%280.789%29%5E2%3D1.867)
After Pulling off hands so that r' is the distance of masses from stool
![I_0'=2\times 1.5\times (r')^2](https://tex.z-dn.net/?f=I_0%27%3D2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2)
Conserving angular momentum
![I_1\omega =I_2\omega _2](https://tex.z-dn.net/?f=I_1%5Comega%20%3DI_2%5Comega%20_2)
![(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62](https://tex.z-dn.net/?f=%285.53%2B1.867%29%5Ccdot%2017.90%3D%285.53%2BI_o%27%29%5Ccdot%2022.62)
![I_0'=1.397\times 0.791](https://tex.z-dn.net/?f=I_0%27%3D1.397%5Ctimes%200.791)
![I_0'=5.851](https://tex.z-dn.net/?f=I_0%27%3D5.851)
![5.53+2\times 1.5\times (r')^2=5.851](https://tex.z-dn.net/?f=5.53%2B2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2%3D5.851)
![2\times 1.5\times (r')^2=0.321](https://tex.z-dn.net/?f=2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2%3D0.321)
![r'^2=0.107009](https://tex.z-dn.net/?f=r%27%5E2%3D0.107009)
![r'=0.327 m](https://tex.z-dn.net/?f=r%27%3D0.327%20m)
Answer:
Qinghai
Step-by-step explanation:
Answer:
Not sure if I was ever able to help you but I hope you have an amazing future<#