By equating both quadratic equations, Brian can determine the point of intersection of both equations. Upon graphing he was able to identify that both share the same vertex but of opposite opening. Based on this, he can say that both equations are equations of parabolas with same vertex but open on different directions.
Wait i need help with that too we have the same assignmen.
If A represents an angle, its complement is 90-A.
If m<1 = 36, then its complement is 90-36 (degrees), or 54 (degrees).
Answer:
Step-by-step explanation:
<u>Quadratic Function</u>
The quadratic function can be expressed in the following form:
Where a is a real number different from 0, and x1, x2 are the roots or zeroes of the function.
From the conditions stated in the problem, we know
x_1=1+\sqrt{2}, \ x_1=1-\sqrt{2}
Substitute in the general formula above:
Operate the indicated product
To find the value of a, we use the y-intercept which is the value of y when x=0, thus
It follows that
Thus, the required quadratic function is
Or, equivalently
Answer: Hope this helps
y = 3/5x + 100
Slope: 3/5
Y-int: 100
Step-by-step explanation:
y = mx + b
<em>replace b with y-int</em>
y = mx + 100
<em>replace m with the slope which is 3/5</em>
y = 3/5x + 100
<em>How do you get slope?</em>
<em>Well I did rise/run with two points so I saw it ran 5 squares and rose only 3.</em>
<em>How do you get the y-int?</em>
<em>Well the y-int is the point where x is 0. So using the point (0,100), since x is 0, the y-int is 100.</em>