Answer:
3x²+(-27x) +0
Step-by-step explanation:
The given expression is :
x + 3x² – 28x
We need to solve this in the form of ax²+bx+c.
we can write the given expression as :
3x²-28x+x = 3x²-27x
= 3x²+(-27x) +0
If we compare the given expression with the general expression, we find that,
a = 3, b = -27 and c = 0
Hence, the required equation is 3x²+(-27x) +0.
Step-by-step explanation:
sin∅=-3/4 in 4 quadrant which sine is negative there
using soh cah toa
sin=opp/hyp
where our opp=-3 and our hyp=4
using pythagoras theorem
hyp²=opp²+adj²
(4)²=(-3)²+adj²
16=9+adj²
16-9=adj²
adj²=7
adj=√7
from soh cah toa
cos∅=adj/hyp
cos∅=√7/4
3! =3 x 2 x 1 = 6
Y!= Y x (y-1) x ... x 1=
Get the decimal version of 26% by moving the decimal (at the end) over to spots, giving you .26. Multiply 50 by this, and you get .26*50=13. : )
Answer:
c. 0 and 7
Step-by-step explanation:
