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Irina-Kira [14]
3 years ago
5

An online music store offers 2 downloads for $7.50. Another online music store offers 12 downloads for $20.20 which store offers

the better deal
Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

the second store has the better deal.

Step-by-step explanation:

12 ÷ 2 = 6

7.5 × 6 = 45

20.2 < 45

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lys-0071 [83]

Answer:

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What is 7/10-1/2 for subtracting fractions
Charra [1.4K]
I'm guessing you mean to find the answer. So find a common denominator, which is 10. You can leave 7/10 alone. Now multiply by 5 on both the numerator and denominator of 1/2. It would be 5/10. Now subtract 7/10-5/10. The answer is 2/10. It can be simplified to 1/5. The answer now would be: 1/5
I hope this helps. :-) 
7 0
3 years ago
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The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
3 years ago
Solve for x.<br> -30 = 5(x + 1) <br>x=​
Alecsey [184]

Answer: -7

Step-by-step explanation:

-30 = 5(x + 1)

-30 = 5x + 5.  ( After distrbuting the 5)

-5.            -5

-30 - 5. = 5x

-35 = 5x

x = -7

5 0
3 years ago
Graph the solutions of the inequality
Fiesta28 [93]

Answer:

The graph in the attached figure

Step-by-step explanation:

Graph the solution of the inequality

t\leq -4

we know that

The solution is the interval ---> (-∞,-4]

All real numbers less than or equal to -4

In a number line the solution is the shaded area at left of t=-4 (closed circle, because the number -4 is included in the solution))

using a graphing tool

The graph in the attached figure

6 0
3 years ago
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