Answer:
This sum is the sum of an arithmetic sequence. There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.
A nice approach for this sequence is the following. Notice that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.
There are n of these pairs. So the desired sum is n x (first number + last number). But the first number is 1 and the last on is 2n. Thus the desired sum is n(1 + 2n).
Hope this helps!!
Mark Brainleast!!!!!!!!!!!
1.Combine multiplied terms into a single fraction
2. Multiply by 1
3. Subtract 6 from both sides of the equation
4.Simplify
5.Subtract 3x from both sides of the equation
6.Simplify
7.Multiply all terms by the same value to eliminate fraction denominators
8.Simplify
9.Divide both sides of the equation by the same term
10.Simplify
Solution:x=4
Answer:
No, it's not
Step-by-step explanation:
If Triangle ABC is similar to triangle DEF, then ∠A is congruent to ∠D, ∠B is congruent to ∠E, and ∠C is congruent to ∠F.
If ∠E = 40°, then ∠B = 40°.
There are 180° in a triangle. If ∠A = 35° and ∠B = 40°, then ∠C = 180° - 35° - 40°.
180 - 35 - 40 = 105°
m∠C = 105°
x+(x+2)=116. Simplify that to 2x+2=116, subtract 2 from both sides to get 2x=114, and then divide both sides by 2 to get x=57. That would be the first integer, so the second would then be 59. So there's your answer: The two consecutive odd integers are 57 and 59.Answer:
Step-by-step explanation:
