<span><span> Let ABC be an isosceles triangle with AB = AC. Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC). Thena)<span> </span>Triangle ABM is congruent to triangle ACM.b)<span> </span>Angle ABC = Angle ACB (base angles are equal)c)<span> </span>Angle AMB = Angle AMC = right angle.d)<span> </span>Angle BAM = angle CAM
</span></span>
This should help
60 sec = 1min
60min = 1 hour
24hour = 1day
7 days = 1 week
around 4.3 weeks = 1month
12 months = 1 year
or you could use 365 days and times that by 24 than times that by 60 to get mins and again by 60 to get seconds.
hope this helps
Answer:
The correct answer is letter C
Step-by-step explanation:
Answer: p < -3/5
Step-by-step explanation:
2p - 4 < -3p - 7
+3p +3p
------------------------
5p - 4 < -7
+4 +4
------------------------
5p < -3 (divide by 5)
p < -3/5
Answer:
5 meters.
Step-by-step explanation:
Given:
Mr. Dyer is leaning a ladder against the side of his house to repair the roof.
The top of the ladder reaches the roof, which is 3 meters high.
The base of the ladder is 4 meters away from the house, where Mr. Dyer's son is holding it steady.
Question asked:
How long is the ladder?
Solution:
<em>Here we found that a right angle triangle is formed in which base and height is given and we have to find the longest side of the triangle.</em>
Base = 4 meters
Height = 3 meters
Length of the ladder = ?
<u>By Pythagoras theorem:
</u>
Square of longest side = Square of base + Square of height



Taking root both side :-
![Longest\ side = \sqrt[2]{5\times5} \\ Longest\ side = 5](https://tex.z-dn.net/?f=Longest%5C%20%20side%20%3D%20%20%5Csqrt%5B2%5D%7B5%5Ctimes5%7D%20%5C%5C%20%20Longest%5C%20%20side%20%3D%20%205)
Thus, length of ladder is 5 meters.