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ladessa [460]
3 years ago
5

What is 5000,30 divide 3000 and multiply it bye 10 and divid it by 1000

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:I don’t understand too

Step-by-step explanation:

Sorry I can’t help you

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Describe how to transform the graph of f into the graph of g. f(x) = x2 and g(x) = -(-x)2 The graph shifts left one unit. Reflec
slega [8]

Answer:

Reflect the graph of f across the y-axis and then reflect across the x-axis.

Step-by-step explanation:

Reflection rules:

Reflection over x -axis:(x,y)→(x,-y)

Reflection over y-axis : (x,y)→(-x,y)

Graph:y= f(x)=x^2

We are given that the graph of f into the graph of g.

f(x) = x^2 and g(x) = -(-x)^2

Reflect over y axis.

Reflected graph =(-x)^2

Reflect the obtained graph over x axis

g(x)=-(-x)^2

So, Option B is true

Hence Reflect the graph of f across the y-axis and then reflect across the x-axis.

7 0
3 years ago
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ahrayia [7]

Answer:

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3 0
4 years ago
Read 2 more answers
I need help with this
BigorU [14]

no u can only buy 6, or u dont have enough money for 7

6 0
3 years ago
Evaluate the amount of work done by the force field F(x,y)=1x2i+yexjF(x,y)=1x2i+yexj on a particle that moves along the curve C:
suter [353]

Answer:

\frac{7}{3} + \frac{e^2 - e}{2}

Step-by-step explanation:

By definition:

Work done along the path is the line integral along that path denoted as:

Work Done = \int\limits^C {F} \, dr

Note:  dr = dx i + dy j

Given that: F (x,y) = x^2 i + ye^x j

F (x, y) dot product with dr = x^2 dx + ye^x dy

Work done = \int\limits^C {(x^2 dx + ye^x dy)}  ... Eq 1

Given that C: y = \sqrt{x-1}

dy = \frac{dx}{2\sqrt{x-1} }

Replace the value of y and dy in Eq 1

Work done =  \int\limits^C ({x^2 + \frac{e^x}{2} }) \, dx

Limits of x are 1 to 2 respectively

Work done =  \int\limits^2_1 ({x^2 + \frac{e^x}{2} }) \, dx

= (\frac{x^3}{3} + \frac{e^x}{2})\limits^2_1

Evaluate limits to obtain

Work Done = \frac{7}{3} + \frac{e^2 - e}{2}

3 0
3 years ago
Connor runs at a constant rate. It takes him 34 minutes to run 4 miles.
slavikrds [6]

Given:

Connor runs at a constant rate.

It takes him 34 minutes to run 4 miles.

To find:

The linear equation in two variables that represents the given situation.

Solution:

Let y be the distance covered by Connor in miles and x be the time in minutes.

It is given that Connor needs 34 minutes to run 4 miles. So, the linear equation passes through the point (34,4,) and the rate of change is:

m=\dfrac{Distance}{Time}

m=\dfrac{4}{34}

Using the point slope, the equation of the linear function is:

y-y_1=m(x-x_1)

y-4=\dfrac{4}{34}(x-34)

y-4=\dfrac{4}{34}x-4

y=\dfrac{4}{34}x

Therefore, the correct option is D, i.e., y=\dfrac{4}{34}x.

4 0
3 years ago
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