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AlexFokin [52]
3 years ago
14

Solve the system of equations using the substitution method.

Mathematics
2 answers:
andre [41]3 years ago
8 0
Answer: (-0.0549,-1.0732)
WARRIOR [948]3 years ago
7 0

Answer:

(6,7)

Step-by-step explanation:

took the test, was correct.

x= 6, y=7

solve for the first variable in one of the equations, then substitute the result into the other equations.

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What is the length of the hypotenuse
ss7ja [257]

Answer:

15

Step-by-step explanation:

The Pythagorean's Theorem states that a^2 + b^2 = c^2, so 81 + 144 = 225, and 225 square rooted is 15.

6 0
3 years ago
Read 2 more answers
I need help I tried to do this question with one C and with two C
OverLord2011 [107]

There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.

Solving for small c..

C = \frac{Wtc}{1,000}   \\\\ 1,000C = Wtc \\\\\frac{1,000C}{Wt}= c

So it's the answer shown in the picture, but it  should be a capital W instead of a lowercase w.  






3 0
3 years ago
Can a triangle with side lengths 7, 25, and 19 be a right triangle?
NARA [144]

Well, the Pythagorean theorem is helpful.

Does 7^2+19^2=25^2?

no it desn't, so no it is not a right triangle

7 0
3 years ago
X^2 + 32x + 256 = 1<br>please show steps​
Elena L [17]

\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}

<h2>Explanation:</h2>

In this case, we have the following equation:

x^2+32x+256=1

But we can write this equation as:

x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0

So this final result is a quadratic equation written in Standard Form (ax^2+bx+c=0). We need to find the solutions to this equations, so let's use quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}

<h2>Learn more:</h2>

Quadratic Equations: brainly.com/question/10278062

#LearnWithBrainly

3 0
3 years ago
5 (4z+6)-2(z-4)=2 (2w^2+7w-3)
love history [14]
If you are solving for "z", the answer is
z=2w^2+7w/10 -2
4 0
3 years ago
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