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Serggg [28]
2 years ago
15

By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00pm positive or negative?

Mathematics
1 answer:
Ad libitum [116K]2 years ago
6 0

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.​

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

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nirvana33 [79]

Answer:

k = -7

Step-by-step explanation:

Solve for k:

-7 k - 44 = k + 12

Subtract k from both sides:

(-7 k - k) - 44 = (k - k) + 12

-7 k - k = -8 k:

-8 k - 44 = (k - k) + 12

k - k = 0:

-8 k - 44 = 12

Add 44 to both sides:

(44 - 44) - 8 k = 44 + 12

44 - 44 = 0:

-8 k = 12 + 44

12 + 44 = 56:

-8 k = 56

Divide both sides of -8 k = 56 by -8:

(-8 k)/(-8) = 56/(-8)

(-8)/(-8) = 1:

k = 56/(-8)

The gcd of 56 and -8 is 8, so 56/(-8) = (8×7)/(8 (-1)) = 8/8×7/(-1) = 7/(-1):

k = 7/(-1)

Multiply numerator and denominator of 7/(-1) by -1:

Answer: k = -7

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