now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then
![\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill](https://tex.z-dn.net/?f=%5Cbf%20y%20%3D%20x%20-%2028%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bwhen%20x%20%3D%2016%7D%7D%7By%20%3D%2016%20-%2028%7D%5Cimplies%20y%20%3D%20-12%20%5C%5C%5C%5C%5C%5C%20y%20%3D%20x%20-%2028%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bwhen%20x%20%3D%2012%7D%7D%7By%20%3D%2012%20-%2028%7D%5Cimplies%20y%20%3D%20-16%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%28%5Cstackrel%7Bx%7D%7B16%7D~~%2C~~%5Cstackrel%7By%7D%7B-12%7D%29%5Cqquad%2C%5Cqquad%20%28%5Cstackrel%7Bx%7D%7B12%7D~~%2C~~%5Cstackrel%7By%7D%7B-16%7D%29~%5Chfill)
First lets start by making the denominators the same. I multiplied the 4 by 5 and 10 by 2.
-25/20 = x -14/20
Add 14/20 on both sides (do the opposite to cancel out and whatever you do to one side you need to do to the other.
You should get -11/20 = x
Answer:
The expression for the nth term is Tn = 8n -7
Step-by-step explanation:
Here, we are to find an expression for the nth term of the sequence.
Mathematically, the nth term of an arithmetic sequence can be expressed as;
Tn = a + (n-1)d
for T2, the equation is
a + d = 9
for T4, the equation is
a + 3d = 25
we can substitute the equation of T2 into T4 but we first need to rewrite T4
a + d + 2d = 25
9 + 2d = 25
2d = 25 -9
2d = 16
d = 16/2
d = 8
now since a + d = 9
a = 9-d
a = 9-8
a = 1
So the expression for the nth term would be;
1 + (n-1)8
1 + 8n - 8
= 8n -8+1
= 8n -7
Answer: f^-1(x)=-7x+3 maybe ? i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
CORN VIRUS IS A
HOAX
