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lozanna [386]
2 years ago
14

-5/4 = x -7/10 solve for x and show work please

Mathematics
1 answer:
tekilochka [14]2 years ago
6 0
First lets start by making the denominators the same. I multiplied the 4 by 5 and 10 by 2.

-25/20 = x -14/20
Add 14/20 on both sides (do the opposite to cancel out and whatever you do to one side you need to do to the other.
You should get -11/20 = x
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A outlier is something spread out from the rest for example you have the numbers 12, 9, 3,10, 16, 89 obviously the outlier is 89 so the number spread from the rest 
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My questions are in the picture please help
Marrrta [24]

21.

So to solve for the value of a variable in an equation, you would need to isolate x on one side. The first thing you have to do is multiply 2 and (x + 7) together, which can be rewritten as 2(x) + 2(7). After multiplying, your equation would be: 2x+14+3x=12 , or A.

22.

So the rule with multiplying exponents with the same base is to add the exponents together, and the rule with dividing exponents with the same base is to subtract the exponents. Your equation will be simplified as such:

4^{(3+4)-9}\\ 4^{7-9}\\ 4^{-2}

Now the rule with converting negative exponents into fractions is x^{-m}=\frac{1}{x^m} . In this case, 4^-2 would turn into \frac{1}{4^2} , or C, which is your final answer.

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2 years ago
What is the CIRCUMFERENCE of a circle with a radius of 18m?
Lyrx [107]

Answer:

the first one is  113.04m

the second one is 615.44 cm

the third one is 530.66 ft

the fourth one is 163.28 in

the fifth one is 31.4 m

the sixth one is 28.26 m

the seventh one is 314

the eightth one is 50,24

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2 years ago
I WILL GIVE BRAINLIEST
adelina 88 [10]

Answer: 2x - 1 (+x) =19

4 0
2 years ago
At a production process, the produced items are tested for defects. A defective unit is classified as such with probability 0.9,
Snezhnost [94]

Answer:

We use Baye's theorem:  P(A)P(B|A) = P(B)P(A|B)

with (A) being defective and

(B) marked as defective

we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)

Since  P(A) = 0.1 and P(B|A)=0.9,

P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9

and

P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15

put these values in eq(2)

P(B) = (0.1 × 0.9) + (0.9 × 0.15)

       = 0.225 put this in eq(1) and solve for P(B)

P(B) = 0.4

6 0
2 years ago
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