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makvit [3.9K]
3 years ago
9

I feel like im gonna drown in math, help me pls

Mathematics
2 answers:
coldgirl [10]3 years ago
8 0
264 people would be the answer to this problem
BaLLatris [955]3 years ago
5 0

Answer: 264 people

Explanation: 48/70= 0.6857142857142857 which multiplied by 385 is 264

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qaws [65]
It should be 2, because your adding 2 each time for the y value. When your finding slope it’ll always be the change in y over the change in x. Hope this helps!!
8 0
3 years ago
Can someone help me please will give brainliest
wolverine [178]

Answer:

  see below

Step-by-step explanation:

Each point moves to half its previous distance from P. It is probably easier to count grid squares on the graph than it is to do the math on the coordinates.

If you're doing the math on the coordinates, it is convenient to use P = (0, 0), then multiply each of the coordinates of A, B, and C by 1/2. For example:

  A' = (1/2)A = (1/2)(8, 4) = (4, 2)

8 0
4 years ago
(please hurry) Which expression is equivalent to -6x³•x•y²•y^6?
Naddik [55]

Answer:

The third one

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A doctor visits a patient in morning rounds. In how many different ways can the doctor visit 5 patients during morning rounds
LuckyWell [14K]
10 times because 5 times 2 is 10
4 0
4 years ago
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

4 0
4 years ago
Read 2 more answers
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