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3 years ago

WILL GIVE BRAINLY Find the perimeter of the figure below, in meters.

Mathematics

1 answer:

yan [13]3 years ago

3 0

Answer:

$147.6\:\mathrm$

Step-by-step explanation:

The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.

Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

$9.8+9.8+11.7+9.8+21.5+21+11.7+9.8+31.3+11.2=\boxed{147.6\:\mathrm{m}}$

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.

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What are the coordinates of the point (-1,9) after a clockwise rotation of 90 degree about the origin

Elina [12.6K]

The rule for clockwise rotation of 90 degrees about the origin is (-y, x).

So (-1,9) would now be (-9,1).

Hope this Helps!!

7 0

3 years ago

Help me solve please

Lisa [10]

Answer:

degree measure of arc AB = 120°

length of arc AB = 40π/3 in.

Step-by-step explanation:

arc AB has the same measure as its central angle. So, arc AB = 120°

120 is 1/3 of 360, Therefore, the length of arc AB is 1/3 of the circumference.

Therefore, the

length of arc AB = 1/3πd = 1/3π(40) =

= 40π/3 in.

5 0

3 years ago

How many batches of cookies can you make if you have 8 cups of flour and recipe calls for 3/4 per batch?

vodka [1.7K]

Answer:

10 batches i think, sorry if im wrong

Step-by-step explanation:

6 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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3 years ago

Find the x- and y-intercepts of the equation -5x+y=30

ArbitrLikvidat [17]

Answer:

all work is shown and pictured

6 0

3 years ago

Read 2 more answers