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NISA [10]
3 years ago
14

Solve for x in the equation 3x^2-18x+5=47

Mathematics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

Option 1

Step-by-step explanation:

3 {x}^{2} - 18x + 5 = 47

=  > 3 {x}^{2}  - 18x + 5 - 47 = 0

=  > 3 {x}^{2}  - 18x - 42 = 0

=  > 3( {x}^{2}  - 6x - 14) = 0

=  >  {x}^{2}  - 6x - 14 = 0

We know that

x =  \frac{ - b +  \sqrt{d} }{2a} \:  or  \: \frac{ - b -  \sqrt{d} }{2a}

Where D = Discriminant of the eqn.

Discriminant of the above eqn.=

{b}^{2}  - 4ac =  {( - 6)}^{2}  - 4 \times ( - 14) \times 1 = 92

So,

x =  \frac{ - ( - 6) +  \sqrt{92}  }{2 \times 1}  \: or \:  \frac{ - ( - 6) -  \sqrt{92}  }{2 \times 1}

=  > x =  \frac{6 + 2 \sqrt{23} }{2} \: or \:  \frac{6 - 2 \sqrt{23} }{2}

=  > x = (3 +  \sqrt{23} ) \: or \: (3 -  \sqrt{23} )

Elina [12.6K]3 years ago
5 0

Answer:

<h2>x=3±√23</h2>

thats the answer ^^

Step-by-step explanation:

plz give me brainlyest i need it

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