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xxTIMURxx [149]
3 years ago
12

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

  • <em><u>d.the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em>

Step-by-step explanation:

<em><u>brainleist</u></em><em><u> </u></em><em><u>bunch</u></em><em><u>☺️</u></em>

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At the beginning of spring, Arianna planted a small sunflower in her backyard. When
zhannawk [14.2K]

Answer:

3 weeks: 21.5 inches

w weeks: 20+0.5w inches

Step-by-step explanation:

Equation: 20+0.5w.

20 was when it was first planted and 0.5 is the amount it grows per week.

6 0
3 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
3 years ago
Which is the equation for the nth term of the geometric sequence-2, 8, -32, ... ?
Cerrena [4.2K]

Answer:

54

Step-by-step explanation:

4 0
3 years ago
What are the roots of the polynomial equation x3-7x=6x-12?
Ilia_Sergeevich [38]
This is not a polynomial equation unless one of those is squared.  As it stands x=-.833.  If you can tell me which is squared I can help solve the polynomial.

Ok, that is usually notated as x^3 to be clear.   I'll solve it now.

x^3-13x-12=0

Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1

Then you have x^2-x-12 now you complete the square.

Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:

The x-term coefficient = −1

The half of the x-term coefficient = −1/2

After squaring we have (−1/2)2=1/4

When we add 1/4 to both sides we have:

x2−x+1/4=12+1/4

STEP 3: Simplify right side

x2−x+1/4=49/4

STEP 4: Write the perfect square on the left.

<span>(x−1/2)2=<span>49/4
</span></span>

STEP 5: Take the square root of both sides.

x−1/2=±√49/4

STEP 6: Solve for x.

<span>x=1/2±</span>√49/4

that is,

<span>x1=−3</span>

<span>x2=4</span>

<span>and the one from before </span>

<span>x=-1</span>

7 0
4 years ago
Read 2 more answers
On a coordinate grid, a park is located at (3,0) and the pool is located at (-3,3). If the tennis courts are the midpoint betwee
Lemur [1.5K]

I think c if not sorry have a good day

7 0
3 years ago
Read 2 more answers
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