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slega [8]
3 years ago
14

I mark as brainliest ​

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

2 quarts

Step-by-step explanation:

2 pints = 1 quart

so then 4 quart = 1 gallon so there are 2 quarts left.

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Which explanation provides the best real-world senario of the graph​
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i don't know

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You pick a card at random. You put the first card back, and you pick a second card at
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2 years ago
Graph y > x^2 - 5. Click on the graph until the correct one appears.
kenny6666 [7]

y=x^2\\\\for\ x=\pm2\to y=(\pm2)^2=4\to(-2;\ 4);\ (2;\ 4)\\\\for\ x=\pm1\to y=(\pm1)^2=1\to (-1;\ 1);\ (1;\ 1)\\\\for\ x=0\to y=0^2=0\to (0;\ 0)

Shift the graph of the function y = x², 5 units down /look at the picture #1/.

y > x^2-5 /look at the picture #2/ - your answer

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3 years ago
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Cheryl's softball batting average is 0.340, and Karin's is 0.304. Karin say they have the average. What error did she make.
Veronika [31]
Karin's average is smaller than Cheryl's
6 0
3 years ago
PLEASE HELP ME SOLVE
kirill115 [55]

The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .

In the question ,

it is given that

the time taken to vacate the stadium = 20 minutes

number of exits = 25 exits

capacity of the stadium = 25000 spectators .

given that ,

time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .

time taken ∝ number of spectators ∝ 1/number of exits .

to remove the proportionality sign , we write the constant

time taken = k * (number of spectators)/(number of exits) .

20 = k * 25000/25

20 = k * 1000

k = 20/1000

k = 2/100

k = 1/50 = 0.02

So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula

time taken = (0.02)*(21000/15)

= 0.02*1400

= 28

Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28  minutes .

Learn more about Equation here

brainly.com/question/23633125

#SPJ1

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