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Ierofanga [76]
3 years ago
6

A rectangle is inscribed in a circle of radius r. if the width of the rectangle is x, what is the height of the rectangle?

Mathematics
1 answer:
user100 [1]3 years ago
3 0

The diagonal of length 2r forms the hypotenuse of a right angled triangle with  one leg ( the width of the rectangle) = x. So by Pythagoras:-

(2r)^2 = h^2 + x^2      where h = height of the rectangle

h^2 = 4r^2 - x^2

h =  √ (4r^2 - x^2)     answer

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I will try to solve your system of equations.

y=22;−10x+15y=−10

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Step: Substitute22foryin−10x+15y=−10:

−10x+15y=−10

−10x+(15)(22)=−10

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−10x+330+−330=−10+−330(Add -330 to both sides)

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(Divide both sides by -10)

x=34

Answer:

y=22 and x=34Answer:

Step-by-step explanation:

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The width of a rectangle is 9 inches more than 5 times the length. If x represents the length, write an algebraic expression in
larisa86 [58]

Answer:

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Step-by-step explanation:

In order to solve this question we were given an expression that relates both dimensions of the rectangle. This expression in a mathematical form where "x" is the length and "y" is the width is shown bellow:

y = 9 + 5*x

The perimeter of a rectangle is given by:

perimeter = 2*length + 2*width

perimeter = 2*x + 2*(9+5*x)

perimeter = 2*x + 18 + 10*x

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The expression that represents the perimeter of the rectangle is "12*x + 18", where "x" is the length of the rectangle.

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Vedmedyk [2.9K]

<u>Given</u>:

The system of linear equations are x-y=4 and 3x-2y=-5

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<u>Solution</u>:

The solution can be determined using the substitution method.

Let us substitute x=4+y in the equation 3x-2y=-5

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