<span>Given: ΔABC
When written in the correct order, the two-column proof below describes
the statements and justifications for proving the three medians of a
triangle all intersect in one point are as follows:
Statements Justifications
Point F
is a midpoint of Line segment AB </span><span>by Construction
Point E is a midpoint of Line segment
AC
Draw Line segment BE
Draw Line segment FC
Point G is
the point of intersection between
Line segment BE and Line segment FC Intersecting Lines Postulate
Draw Line segment AG by Construction
Point D
is the point of intersection between
Line segment AG and Line segment
BC Intersecting Lines Postulate
Point H lies on Line segment AG such
that
Line segment AG ≅ Line segment GH by Construction
</span><span>Line segment FG is parallel to line segment
BH and Line
segment GE is parallel to line
segment HC Midsegment Theorem
</span><span><span>Line
segment GC is parallel to line segment
BH and Line segment BG is
parallel to
line segment HC Substitution</span>
</span>BGCH is a <span><span><span><span>Properties of a Parallelogram </span>parallelogram (opposite sides are parallel)</span>
</span>Line segment BD
≅ Line segment </span><span><span>Properties of a Parallelogram </span>DC (diagonals bisect each
other)
Line segment
AD is a median Definition of a Median</span>
Thus the most logical order of statements and justifications is: II, III, IV, I
2pirad=360 deg
so
xrad/2pi=ydeg/360
times both sides by 360 to solve for ydeg
180xrad/pi=ydeg
so
7/9pi rad
180(7/9pi)/pi=ydeg
140=ydeg
140 deg
A is answer
6x - 3y = 12
3y = 6x -12
y = 2x -4
slope = 2
