Answer:
1) f(g(0)) = 0
2) g(f(2)) = 2
3) g(g(0)) = 8
Step-by-step explanation:
Here, the given functions are:
g(x) = 3 x +2 and f(x)= (x-2)/3
1. Now, f(g(x)) = f(3x+2)
Also, f(3x+2) = (3x+2 -2) /3 = x
So, f(g(x)) = x
⇒ f(g(0)) = 0
2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2
or, g(f(x)) = x
⇒ g(f(2)) = 3((2)-2/3) +2 = 2
or, g(f(2)) = 2
3. g(g(0)= g( 3 (0) +2) = g(2)
Now, g(2) = 3(2) + 2 = 6 + 2 = 8
or, g(g(0)) = 8
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
B
Step-by-step explanation:
Answer:
y = ac / (a - b - c)
Step-by-step explanation:
y(a - b) = c(y + a)
Distribute
ay - by = cy + ac
Subtract cy from both sides
ay - by - cy = ac
Factor out y
y(a - b - c) = ac
Divide both sides by (a - b - c)
y = ac / (a - b - c)
