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ratelena [41]
3 years ago
10

PLEASE HELP

Mathematics
1 answer:
Maslowich3 years ago
8 0

If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.

So, what are the chances of it not occurring in 1 trip?

1−.37=.63

What about not occurring in 2 trips?

(1−.37)⋅(1−.37)=.63⋅.63=.3969

Now what about not occurring in 4 trips?

.63^4 = 0.15752961

We must subtract this value from 1

(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:

1−0.15752961 = .84247039

TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.

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Step-by-step explanation:

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Licemer1 [7]
6. Answer: B
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6 0
3 years ago
PLEASE HELP ITS DUE AT MIDNIGHT
antiseptic1488 [7]
Answer:
The rest of the question is the attached figure
The percent change =
If (+ve) increase and if (-ve) decrease
Part A: What is the percent of change in the cost of a pizza?
The initial price = $7.5
The final price = $9
The percent change = %
Part B: What is the percent of change in the cost of a cheeseburger?
The initial price = $5
The final price = $6.5
The percent change = %
Part C: What is the percent of change in the cost of a serving fries?
The initial price = $2
The final price = $4.5
The percent change = %
Part D: What is the percent of change in the cost of a hot dog?
The initial price = $2.5
The final price = $2
The percent change = %
i found this online i hope if helps you

3 0
3 years ago
Read 2 more answers
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