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3 years ago

How to tell if a function is continuous or discontinuous?

1 answer:

3 0

A functions is discontinuous if it has stuff like holes, jumps, or vertical asymptotic. In addition, it's continuous if it stays in a line the whole time (it doesn't have to be straight or anything!)

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The complement of a right angle is an obtuse angle.

harkovskaia [24]

Wrong , actually the complement of an obtuse angle is a right angle

yw brodie

4 0

3 years ago

Find the 12th and 37th term for each arithmetic sequence.

shutvik [7]

Answer:

3. f(12) = -10; f(37) = -60

4. f(12) = -102; f(37) = -352

Step-by-step explanation:

3. Put the numbers in the formula and do the arithmetic:

f(12) = 12 -2(12-1) = 12 -22 = -10

f(37) = 12 -2(37-1) = 12 -72 = -60

4. The explicit formula for an arithmetic sequence with first term a1 and common difference d is ...

an = a1 +d(n -1)

Your sequence has a first term a1=8 and a common difference d=-10.

As above, fill in the numbers and do the arithmetic.

f(12) = 8 -10(12 -1) = -102

f(37) = 8 -10(37-1) = -352

5 0

3 years ago

Please answer question 11

irinina [24]

Answer:

I'm pretty sure it's 4

Step-by-step explanation:

association property of addition involves well addition and that's what it shown in y+0=y

6 0

3 years ago

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0

3 years ago

Find the measure of XY. Assume that segments that appear to be tangent are tangent. Round your final answer to the nearest tenth

Slav-nsk [51]

Answer:

Solution given:

7x-29=2x+16[length from the circumference of circle is equal to same point]

7x-2x=16+29

5x=45

x=45/5=9

now.

XY=2×9+16=18+16=34 is your answer

5 0

3 years ago