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Ymorist [56]
3 years ago
15

If the sum of 2/3 and 3/4 is divided are the product of 2/3 and 3/4 what is the quotient?

Mathematics
1 answer:
Virty [35]3 years ago
8 0
The photo shows the answer

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Find the area of this composite figure
ella [17]

Answer:

81 m²

Step-by-step explanation:

6x10=60

1/2(6)(7)=21

60+21=81

3 0
3 years ago
What percent of $375 is $11.25 and what percent of $56.25 is $11.25?
Angelina_Jolie [31]

Answer:

3%percent of $375 is $11.25 and 20% of $56.25 is $11.25 .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ values}

First Part

As given

Total value = $375

Part value = $ 11.25

Put values in the formula

Percentage = \frac{11.25\times 100}{375}

Percentage = \frac{1125}{375}

Percentage = 3 %

Second Part

Total value = $56.25

Part value = $11.25

Put the values in the formula

Percentage = \frac{11.25\times 100}{56.25}

Percentage = \frac{1125}{56.25}

Percentage = 20%

Therefore 3%percent of $375 is $11.25 and 20% of $56.25 is $11.25 .

3 0
3 years ago
Read 2 more answers
HELP I NEED HELP ASAP
tatiyna

Answer:

D) 8x²-172x+120

Step-by-step explanation:

Length=2(-2x+20)+6

Width=-2x+20

(-4x+40+6)(-2x+20)

(-4x+46)(-2x+20)

8x²-80x-92x+920

8x²-172x+920

5 0
2 years ago
Tyler and frazer weigh a total of 23kg.tyler is 7kg heavier than frazer.How much do they each weigh
kifflom [539]

Step-by-step explanation:

if tyler is 7kg

frazer is 23-7kg

so he is 16kg

3 0
3 years ago
Read 2 more answers
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
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