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3 years ago

When dividing two different Integers what would their sign be?

Mathematics

2 answers:

Mama L [17]3 years ago

7 0

Answer:

Negative

Step-by-step explanation:

When you divide two integers with the same sign, the result is always positive. Just divide the absolute values and make the answer positive. When you divide two integers with different signs, the result is always negative. Just divide the absolute values and make the answer negative.

skelet666 [1.2K]3 years ago

7 0

Answer:

Negative UwU

Step-by-step explanation:

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Dan bought a new computer for $900. Each year, the value of the computer decreased by 25% of the previous year’s value.

Anna35 [415]

Answer:

$29, that is the answer for this question

8 0

3 years ago

PLEASE HELP ME SOLVE this

Alisiya [41]

Answer:

y=-12/11

Step-by-step explanation:

y-(-12/11)=0(x-(-12/13))

y+12/11=0(x+12/13)

y+12/11=0

y=-12/11

Since the slope equals 0, then the line is horizontal.

3 0

3 years ago

A tree is leaning at a 5° angle from vertical, making an 85° angle with the ground. When the sun is at a 65° angle of elevation,

Vinvika [58]

D = 25 ft is the length of a shadow. L - the length of a tree.
Two angles are 85° and 65° and the third is 180° - ( 65° + 85° ) =
= 180° - 150° = 30°.
We will use the Sine Law:
25 / sin 30° = L / sin 65°
25 / 0.5 = L / 0.9063
25 * 0.9063 = 0.5 L
22.6577 = 0.5 L
L = 22.6577 : 0.5
L = 45.3 ft.
Answer: the approximate length of the tree is 45.3 ft.

3 0

3 years ago

The following table shows how the average constituency changes for two regional governing boards, joshua and salinas, when a new

AVprozaik [17]

The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be

<h3>How to calculate the values?</h3>

The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be:

= (1520 - 1232)/1232

= 288/1232

= 0.234

The relative unfairness of an apportionment that gives a new board member to salinas rather than to Joshua will be:

= (1448 - 1333)/1333

= 115/1333

= 0.086

The regional governing board that should receive the new board member is Salinas.

Learn more about tables on:

brainly.com/question/3632175

#SPJ1

5 0

2 years ago

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago