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Maksim231197 [3]
2 years ago
9

Helpp me plssssss????

Mathematics
1 answer:
snow_tiger [21]2 years ago
3 0

Answer:

C

Step-by-step explanation:

The radius is 4 making the diameter 16 you need the other side since in half so that leaves you with answer C...16\pi yd^2

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Esteban wants to take out a $5,000 loan from the bank and is offered two choices. If he pays the loan back within 3 years, he wi
castortr0y [4]

Answer:

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Step-by-step explanation:

8 0
3 years ago
If the lines a and b in the diagram below are parallelm why do angles 2 and 6 measure 60 degree angles
Bas_tet [7]
Angles 2 and 6 are corresponding angles, which would explain why they are congruent if lines a and b are parallel, but there is nothing in the problem to explain that any of the angles equals 60 degrees since no measurements were given in the diagram.
8 0
3 years ago
The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid
ryzh [129]

Given:

The bases of a trapezoid lie on the lines

y=2x+7

y=2x-5

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

On comparing y=2x+7 with slope intercept form, we get

m_1=2,b_1=7

On comparing y=2x-5 with slope intercept form, we get

m_2=2,b_2=-5

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

m=m_1=m_2=2

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

b=\dfrac{b_1+b_2}{2}

b=\dfrac{7-5}{2}

b=\dfrac{2}{2}

b=1

So, the y-intercept of the required line is 1.

Putting m=2 and b=1 in slope intercept form, we get

y=2x+1

Therefore, the equation of line that contains the midsegment of the trapezoid is y=2x+1.

7 0
2 years ago
You invest $90 now its worth $150 the new value is what percent of the original value
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8 0
3 years ago
HELP PLS Given a polynomial function f(x), describe the effects on the Y-intercept, regions where the graph is increasing and de
Mashcka [7]
1. Remarks:

f(x) to f(x)-3 is the whole graph of f(x), shifted 3 units down. 

f(x) to -2f(x): 

The effect of "multiplication by -" is that the whole graph is reflected with respect to the x axis, so it is turned upside down.
 
The effect of "multiplication by 2" is that every point is "stretched vertically by a factor of 2" . So for example the point (-1, -4) in the original function, becomes (-1, -8) in the second one. Or (2, 5) would become (2, 10). 

The only points that do not change (are not streched vertically) are the roots. For example if (4,0) is an x-intercept (a root) in the original function, (4,0) is still a root in the second one because  2 times 0 is still 0.


2. Consider the polynomial function of degree n: 

f(x)= a_{n} x^{n} +a_{n-1} x^{n-1}+....+a_{2} x^{2}+a_{1} x^{1}+a_{0}

a. Y-intercept

The y - intercept is the value of the polynomial function at x=0. 
So it is f(0)=a_{0}, that is, the constant term of f(x)

in f(x)-3 the y intercept is shifted 3 units down as any other point, so it becomes  a_{0}-3

In -2f(x), the y-intercept a_{0} becomes -2a_{0}

b. Regions of f decreasing or increasing

f(x)-3 is f(x) just shifted down 3 units, so they are both increasing and decreasing in the same intervals of x

-2f(x) is f(x) turned upside down, so -2f(x) is increasing in all intervals f(x) is decreasing and it is decreasing in all intervals f(x) is increasing.

c. End behaviors

By now it is clear that end behaviors of f(x) and f(x)-3 are same, and f(x) with -2f(x) are opposite

d. Evenness, oddness

If f(x) is even, then f(x)=f(-x)

Let g(x)=f(x)-3

g(x)=f(x)-3=f(-x)-3=g(-3), so in this case f(x)-3 is even

If f(x) is odd, then f(-x)=-f(x)

g(x)=f(x)-3=-f(-x)-3,

so -g(x)=f(-x)+3

g(-x)=f(-x)-3,  

so g(-x) is not equal to -g(x). Which means f(x)-3 is not odd if f(x) is


Consider f(x)=-2f(x)

If f(x) is even, f(x)=f(-x)

g(x)=-2f(x)=-2f(-x)
g(-x)=-2f(-x)

So g(x)=g(-x), which means -2f(x) is even if f(x) is even

If f(x) is odd, f(x)=-f(-x)

let g(x)=-2f(x)=-2(-f(-x))=2f(-x)

g(-x)=-2f(-x)=-2(-f(x))=2f(x)

so g(-x) is not equal to -g(x), thus -2f(x) is not odd if f(x) is odd.

The conclusions about oddness and evenness can be also derived from the discussions about the graphs.
 

6 0
3 years ago
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