Answer:
![\left(2x-7\right)\left(5x^2-6\right)](https://tex.z-dn.net/?f=%5Cleft%282x-7%5Cright%29%5Cleft%285x%5E2-6%5Cright%29)
Explanation:
![\hookrightarrow\sf 10x^3-35x^2-12x+42](https://tex.z-dn.net/?f=%5Chookrightarrow%5Csf%2010x%5E3-35x%5E2-12x%2B42)
using associative property, separate
![\hookrightarrow\sf \left(10x^3-35x^2\right)+\left(-12x+42\right)](https://tex.z-dn.net/?f=%5Chookrightarrow%5Csf%20%5Cleft%2810x%5E3-35x%5E2%5Cright%29%2B%5Cleft%28-12x%2B42%5Cright%29)
take common term, factorise
![\hookrightarrow\sf 5x^2\left(2x-7\right)-6\left(2x-7\right)](https://tex.z-dn.net/?f=%5Chookrightarrow%5Csf%205x%5E2%5Cleft%282x-7%5Cright%29-6%5Cleft%282x-7%5Cright%29)
final answer
![\hookrightarrow\sf \left(2x-7\right)\left(5x^2-6\right)](https://tex.z-dn.net/?f=%5Chookrightarrow%5Csf%20%5Cleft%282x-7%5Cright%29%5Cleft%285x%5E2-6%5Cright%29)
Answer:
<u>Given inequalities:</u>
- - 2x + 7y < -14
- 4x + 3y > -12
Solution is attached
- The first inequality is zone A
- The second inequality is zone B
- Intersection of two zones is the solution: zone AB
Number 1 = x
Number 2 = y
x = 12y + 6
x + y = 214
You can do multiple methods here. (I am going to do substitution)
So substitute the x equation into the other equation
(12y + 6) + y = 214
13y = 208
y = 16
plug that into an equation to get x
x = 12(16) + 6
x = 198
You can check and see 16 + 198 =214
Answer:
- 1/729
Step-by-step explanation:
math
You can multiply 7.32 x 0.07= 0.5124
Round to $0.51
Or you can find 1% of $7.32 = 0.0732
So 7% would be 7 x 0.0732= $0.5124 Round to 51 cents