Answer:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.
So 292 - 240 = 52 read below or at eight grade level, and that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

80/10=8 packages of plates
80/16=5 packages of napkins
80/8=10 packages of cups
Answer:
The answer is C. The data is skewed right because the time it takes employees to get to work tails off to the right.
Step-by-step explanation
2A)
C is correct.
2B) If x + 13 = 28, solve.

If x = 15 and x + 13 = 28, you can solve it two ways:
1. Plug x into 4x + 26 to get a perimeter of
86, or
2. Redo the equation:

3a. Since the 6z is negative, you want an expression the has 5z - (11z). Answers A and D have that in their answer.
But since the 13 is positive, you want the answer that subtracts the smaller number from the larger. Thus,
D is your answer since it subtracts 2 from 15.
3b) You think about this question the same way; 6z is positive, so the smaller number is being subtracted from the larger, meaning that 11z - 5z is what you look for. C and D are the two that have that, so now let's look at the second term.
The 13 is negative, so you want the answer that has 2 - 15. The answer that has that is
D.
Hope this helps :D